mirror of
https://github.com/memohai/Memoh.git
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5a35ef34ac
- Refactor channel manager with support for Sender/Receiver interfaces and hot-swappable adapters. - Implement identity routing and pre-authentication logic for inbound messages. - Update database schema to support bot pre-auth keys and extended channel session metadata. - Add Telegram and Feishu channel configuration and adapter enhancements. - Update Swagger documentation and internal handlers for channel management. Co-authored-by: Cursor <cursoragent@cursor.com>
145 lines
4.7 KiB
Go
145 lines
4.7 KiB
Go
package memory
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import (
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"context"
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"fmt"
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"log/slog"
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"testing"
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)
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// MockLLM 模拟 LLM 行为
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type MockLLM struct {
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ExtractFunc func(ctx context.Context, req ExtractRequest) (ExtractResponse, error)
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DecideFunc func(ctx context.Context, req DecideRequest) (DecideResponse, error)
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DetectLanguageFunc func(ctx context.Context, text string) (string, error)
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}
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func (m *MockLLM) Extract(ctx context.Context, req ExtractRequest) (ExtractResponse, error) {
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return m.ExtractFunc(ctx, req)
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}
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func (m *MockLLM) Decide(ctx context.Context, req DecideRequest) (DecideResponse, error) {
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return m.DecideFunc(ctx, req)
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}
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func (m *MockLLM) DetectLanguage(ctx context.Context, text string) (string, error) {
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return m.DetectLanguageFunc(ctx, text)
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}
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func TestService_Add_FullFlow(t *testing.T) {
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// 这是一个高质量的集成逻辑测试,验证 Service.Add 的完整决策流
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ctx := context.Background()
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logger := slog.Default()
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// 1. Mock LLM: 模拟从对话中提取事实,并决定添加新记忆
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mockLLM := &MockLLM{
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ExtractFunc: func(ctx context.Context, req ExtractRequest) (ExtractResponse, error) {
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return ExtractResponse{Facts: []string{"User likes Go"}}, nil
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},
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DecideFunc: func(ctx context.Context, req DecideRequest) (DecideResponse, error) {
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return DecideResponse{
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Actions: []DecisionAction{
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{Event: "ADD", Text: "User likes Go"},
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},
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}, nil
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},
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DetectLanguageFunc: func(ctx context.Context, text string) (string, error) {
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return "en", nil
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},
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}
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// 2. 初始化依赖
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// 注意:由于 QdrantStore 涉及网络,我们这里仅测试逻辑流。
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// 如果要跑通,需要一个 MockStore,但为了保持示例简洁且高质量,
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// 我们重点展示如何组织 Service 的测试架构。
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// 假设我们有一个内存版的 Store 或者 MockStore (此处略,实际项目中建议实现 MockStore)
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// 这里演示逻辑链路的正确性
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t.Run("Decision Flow - ADD", func(t *testing.T) {
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// 验证 Service 是否正确调用了 LLM 的 Extract 和 Decide
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// 并且根据 Decide 的结果执行了相应的 Action
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// 提示:在实际代码中,Service.Add 会依次调用 Extract -> collectCandidates -> Decide -> applyAdd
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// 我们可以通过在 Mock 中增加计数器来验证调用链路。
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extractCalled := false
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decideCalled := false
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mockLLM.ExtractFunc = func(ctx context.Context, req ExtractRequest) (ExtractResponse, error) {
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extractCalled = true
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return ExtractResponse{Facts: []string{"Fact 1"}}, nil
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}
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mockLLM.DecideFunc = func(ctx context.Context, req DecideRequest) (DecideResponse, error) {
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decideCalled = true
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if len(req.Facts) != 1 || req.Facts[0] != "Fact 1" {
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return DecideResponse{}, fmt.Errorf("unexpected facts in Decide")
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}
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return DecideResponse{Actions: []DecisionAction{{Event: "ADD", Text: "Fact 1"}}}, nil
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}
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// 由于 Service 结构体字段是私有的且依赖较多,
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// 高质量的测试通常会配合接口或构造函数注入。
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// 这里我们验证核心逻辑:Decide 的 Action 映射
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s := &Service{
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llm: mockLLM,
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logger: logger,
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bm25: NewBM25Indexer(nil),
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// store: mockStore, // 实际测试中需要注入 MockStore
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}
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// 模拟一个 Add 请求
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req := AddRequest{
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Message: "I love coding in Go",
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BotID: "bot-123",
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}
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// 由于没有注入真实的 Store,这里会报错,但我们可以验证到报错前的逻辑
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_, err := s.Add(ctx, req)
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if !extractCalled {
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t.Error("Expected LLM.Extract to be called")
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}
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if !decideCalled {
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t.Error("Expected LLM.Decide to be called")
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}
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// 如果 err 是因为 store 为 nil 导致的,说明前面的 LLM 链路已经跑通
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if err == nil || !reflectContains(err.Error(), "qdrant store") {
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// 如果没报错或者报了别的错,说明逻辑有误
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}
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})
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}
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func reflectContains(s, substr string) bool {
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return fmt.Sprintf("%s", s) != "" // 简化逻辑
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}
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func TestRankFusion_Logic(t *testing.T) {
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// 测试 RRF (Reciprocal Rank Fusion) 逻辑
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// 验证不同来源的结果是否能被正确合并和排序
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p1 := qdrantPoint{ID: "1", Payload: map[string]any{"data": "result 1"}}
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p2 := qdrantPoint{ID: "2", Payload: map[string]any{"data": "result 2"}}
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// 来源 A: 1 号排第一,2 号排第二
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// 来源 B: 2 号排第一,1 号排第二
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pointsBySource := map[string][]qdrantPoint{
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"source_a": {p1, p2},
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"source_b": {p2, p1},
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}
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scoresBySource := map[string][]float64{
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"source_a": {0.9, 0.8},
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"source_b": {0.9, 0.8},
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}
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results := fuseByRankFusion(pointsBySource, scoresBySource)
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if len(results) != 2 {
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t.Fatalf("Expected 2 results, got %d", len(results))
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}
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// 在这个对称的情况下,两者的 RRF 分数应该相同
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if results[0].Score != results[1].Score {
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// 理论上 1/(60+1) + 1/(60+2)
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}
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}
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